w^2+5w+6/3w^2-27

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Solution for w^2+5w+6/3w^2-27 equation: 


w in (-oo:+oo)

w^2+(6/3)*w^2+5*w-27 = 0

3*w^2+5*w-27 = 0

DELTA = 5^2-(-27*3*4)

DELTA = 349

DELTA > 0

w = (349^(1/2)-5)/(2*3) or w = (-349^(1/2)-5)/(2*3)

w = (349^(1/2)-5)/6 or w = (-(349^(1/2)+5))/6

w in { (-(349^(1/2)+5))/6, (349^(1/2)-5)/6 }

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